the answer is E, but I don’t understand how. When I worked it out I
got 8.0 g/molHomework Answers
Rate of effusion is inversely proportional to square root of molar mass
rate = k*sqrt(1/M)
M is molar mass
If we take ratio, above expression becomes
rate(O2)/rate(unknown) = sqrt (M(unknown)/M(O2))
we have:
M(O2) = 32.0 g/mol
rate(O2) = 2.0
rate(unknown) = 1.0
rate(O2)/rate(unknown) = sqrt (M(unknown)/M(O2))
2.0/1.0 = sqrt (M(unknown)/32.0)
sqrt (M(unknown)/32.0) = 2
(M(unknown)/32.0) = 4
M(unknown) = 1.28*10^2 g/mol
Answer: E
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the answer is E, but I don’t understand how. When I worked it out I got 8.0 g/mol - 1. O, effuses twice as fast as a...
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I think I understand but I'm not to sure can some one help?
Thanks
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Need help with the rest and how it was gotten
Parts E and F I dont understand how to solve for them. the front
page has all the data collected and what i was able to solve
for
E. Molar Volume of CO; Gas Trial I {nL 1.030 1. Pressure of dry CO,(g) (atm). See Part C.7 2. Volume of CO-(g) at STP (L). See equation 13.4. ulayanloM ebixo 3. Molar volume of CO,(g) at STP (Lmol). See equation 13.2....
i dont understand why the molecular weight i calculated
(42.012 g/mol) for my unknown liquid (acetone) is less than the
actual molecular weight (58.08 g/mol). what errors could i have
made in my lab that would account for the difference.
Molecular Weight of a Volatile Liquid In this experiment, an amount of liquid more than sufficient to fill the flask when vaporized is placed in a flask of measured volume and mass. The flask is then heated in a boiling...
4. When 10 g of benzene (Molar mass 78 g/mol) reacts with 9 mL of concentrated HNO3 (16 M) and 9 mL of H2SO4 (18 M), 8.1 g of nitrobenzene (molar mass 123 g/mol) and 1.2 g of an unknown compound with a high boiling point are obtained. a. Identify the limiting reagent. b. Calculate the percent yield of nitrobenzene. c. Give the name and structure of the most probable side product with the high melting point. d. Explain, with...
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Just need a little help figuring out how to make the calculations
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