The answers are in red. I just want to know how to correctly solve this...
The answers are in red. I just want to know how to correctly solve this... A hotel claims that 85% of its customers are...
A hotel claims that 85% of its customers are very satisfied with its service. Complete parts a through d below based on a random sample of seven customers. a. What is the probability that exactly six customers are very satisfied? (Round to four decimal places as needed.) b. What is the probability that more than six customers are very satisfied? (Round to four decimal places as needed.) c. What is the probability that less than five customers are very satisfied?...
A hotel claims that 91% of its customers are very satisfied with its service. Complete parts a through d below based on a random sample of 10 customers. Binomial Distribution. (4 points) MUST use the Binomail Distribution function BINOM.DIST() function. Provide your final answer rounded to 4 decimal places in the yellow highlight cell. a) What is the probability that 6 customers are very satisfied? b) What is the probability that more than 6 customers are very satisfied? c) What...
The answers are in red. I just want to know how to correctly solve this... Consider a binomial probability distribution with p = 0.2. Complete parts a through c below. a. Determine the probability of exactly three successes when n = 4. P(3) = 0.0256 (Round to four decimal places as needed.) b. Determine the probability of exactly three successes when n = 6. P(3) = 0.082 (Round to four decimal places as needed.) c. Determine the probability of exactly...
MUST use the Binomail Distribution function BINOM.DIST() function. Provide your final answer rounded to 4 decimal places in the yellow highlight cell. a) What is the probability that 6 customers are very satisfied? b) What is the probability that more than 6 customers are very satisfied? c) What is the probability that less than 6 customers are very satisfied? d) What is the probability that at least 6 customers are very satisfied? A hotel claims that 91% of its customers...
epolled on this issue, A consumer advocate claims that 85 percent of cable television subscribers are not satisfied vwith their cable service. In n attempt to justify this claim, a randomly selected sample of cable subscribers will nthe sample are not satisfied formula to compute the probability that 6 or more subscribers h i end Do not round intormediat ealuations Rund Fnal anewor to in 2 decimal place Bound other final angere to d decimal pics 85 Binomial, n. Probability...
A consumer advocate claims that 85 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue. (a) Suppose that the advocate's claim is true, and suppose that a random sample of 8 cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that 7 or more subscribers in the sample are not satisfied with...
The answers are in red. Please explain all parts According to a research institution, the average hotel price in a certain year was $101.47. Assume the population standard deviation is $18.00 and that a random sample of 36 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. 6- = $3 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $103? P(<$103)...
According to a research institution, the average hotel price in a certain year was $105.12. Assume the population standard deviation is $20.00 and that a random sample of 32 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $106? P(x<$106) (Round to four decimal places as needed.) c. What is the probability...
According to a research institution, the average hotel price in a certain year was $100 21 Assume the population standard deviation is $17 00 and that a random sample of 4 hotels was selected Complete parts a through d befow a, calculate the standard error of the mean Round to two decimal places as needed ) b. What is the probability that the sample mean will be less than $1027 X < $102) : (Round to four decimal places as...
The answers are in red. Please explain all parts, I really want to understand how to tell which quartile to use like part e! A study discovered that Americans consumed an average of 13.5 pounds of chocolate per year. Assume that the annual chocolate consumption follows the normal distribution with a standard deviation of 3.9 pounds. Complete parts a through e below. a. What is the probability that an American will consume less than 9 pounds of chocolate next year?...