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The flow, F, in a river was measured as a function of time, t, and the following data were obtained. F (m/day) t (days) 10 x
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From Table h: t-to = y-FIt (9) tz-ti= 5 and n b-a= foxio6 25-0 5 5 4 x/06 2 X166 Since odd number, n-5 So only Trapezoidal RudFrom art ib) Fo (Vre) Integrahing tyougho F dt Fie 25 Total amount ofueter fleming tn 25 days 25 Fo dt Cltt/k) 25 KFo C(In (

Fo 1+t/K Fo +5/k) put t-5, F(5)=4X106 FIU F5 (i 5/K) 4x106 (ot K= 10 3 25 +t (IA 5/k) Amount of w ater How n 25 days Eo dt +t

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