Question

SN2 + : ОН + : Br Eq. 1 A Br ОН

Hydroxide ion acts as a nucleophile by attacking a carbon atom in 2-bromooctane.

1. Why is that specific carbon atom a good target?

2. Why doesn't the OH attack any other carbons in 2-bromooctane?

3. Why can the carbon atom that is attacked be considered "electron poor"?

Answer 1

| Answer 7 5 3 ki º SN 2 & OH - + 1 + Y OH :Br • Here c-2 carbon atom position is good target. This is due the presence of good leaving group Br atom. Here it can leave as Brion. whiléé in the other carbon atoms, there is directly talons are attached and Hatoms can not leave an tion. secondly if you see the reaction mechanism in SN2 type 8h acts as nucleophile so it will prefer to attack that centre where electron density is less ie in an electrophilic centre. By se As By atom is a electronegative alom, so it drag or with draw c-Bo bonded elections ,so C-2 centre become more electrophilie.so for that he is specific to attack at e-2 position . Oh ion does not attack any other conbon in 2- bromo octane because as OH ion is a nucleophilie so it prefer to attack a electrophilic con centre now careful analysis

Broo - only this carbon centre is electrophic cente, as it has so charge on it. so other than c-2 carbon atom specific target) no othe carbon atours position are not at all electrophilic contre. As well as there is is no such good leaving group present, other @ The carbon atom that is attacked by nucleophile OH can be considered as a election poor". ♡ atom dipole moment] carbon is less electronegetive than Bratom oso C- Br bonded electron shifted to words By atom. it is due for that reason , there is a net dipolemoment. For that there will be a charge seperation, so it will generate less election density, s By so election density is less campair to other carbonaform so called élection poor" Here is no charge separation)