When the concentrations of weak acid [HA] and its conjugate base [A-] are equal, what is the relationship between the pH and pKa based on the Henderson-Hasselback equation?
pH < pKa |
pH = pKa |
pH > pKa |
When the concentrations of weak acid [HA] and its conjugate base [A-] are equal, what is the relationship between the pH...
An unknown weak acid, HA, is used to create a buffer solution. When the concentrations are {HA} = 0.500 M and {A–} = 1.048 M, the pH of the buffer solution is 5.49. Use the Henderson-Hasselbalch equation to find the pKa of the weak acid. Henderson-Hasselbalch equation: pH = pKa + log({A–}/{HA})
Which concentration of a weak acid (HA) and its conjugate base (A-) will make a buffer solution whose pH value is equal to its pKa? (HA) = 0.05 M, (A-) = 0.07 M HA = 0.05 M, (A-) = 0.05 M more than one answer is correct HA = 0.05 M, (A-) = 0.01 M
Consider the reaction between a weak acid (HA) and a weak base (B). If the pKa of HA was 4.6 and the pKa of BH was 10.1, what would be the value of the equilibrium constant to the nearest ones? Hint: Once you write the expression for Keq, you should recognize terms that you can "swap out" with equivalent terms from the Henderson-Hasselbalch equation; this should greatly simplify the math.
Question 39 1 pts A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A) and the conjugate acid of the base (B-H the pKa of HA was 4.8 and the pKa of BH* (i.e., the pKabH of B) was 9.4, what would be the value of the equilibrium constant for the above reaction to the nearest ones? Obviously, by expressing the answer to the nearest ones, we are using too many...
Question 1 (2 points) The relationship between a weak acid and its conjugate base at the 1/2 neutralization point is: the weak acid's concentration is greater than the conjugate base concentration. the weak acid's concentration is less than the conjugate base's concentration the weak acid's concentration is 1/2 the concentration of the conjugate base's concentration the weak acid and conjugate base have the same concentration. Question 2 (3 points) ✓ Saved The pka of acid is 4.8. Determine the acid's...
Consider a buffer composed of the weak acid HA and its conjugate base A?. Part A Which pair of concentrations results in the most effective buffer? Which pair of concentrations results in the most effective buffer? 0.90 M HA; 0.10 M A? 0.50 M HA; 0.50 M A? 0.10 M HA; 0.10 M A? 0.10 M HA; 0.90 M A?
Calculate pH of a weak acid/conjugate base buffer solution. 1. a) Calculate the pH of 650. mL of a 0.211-M solution of acetic acid before and after the addition of 0.123 mol of potassium acetate. pH befor addition = pH after addition = 1 b) Calculate pH of a weak base/conjugate acid buffer solution. A 0.190-M aqueous solution of C2H5NH2 (ethylamine) has a pH of 11.9. Calculate the pH of a buffer solution that is 0.190 M in C2H5NH2 and...
A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A-) and the conjugate acid of the base (B-H+). If the pKa of HA was 4.7 and the pKa of BH+ (i.e., the pKabH of B) was 9.4, what would be the value of the equilibrium constant for the above reaction to the nearest ones? Obviously, by expressing the answer to the nearest ones, we are using too many figures than is...
In a weak acid when [HA]=[A-]the pH = the pKa. What is the pH after adding 0.50 moles HCl to a solution of HA =1 mole and A- = 1 mole. The pKa of the weak acid = 4
Design a buffer that has a pH of 4.77 using one of the weak acid/conjugate base systems shown below. Weak Acid Conjugate Base Ka pKa HC2O4- C2O42- 6.4×10-5 4.19 H2PO4- HPO42- 6.2×10-8 7.21 HCO3- CO32- 4.8×10-11 10.32 How many grams of the potassium salt of the weak acid must be combined with how many grams of the potassium salt of its conjugate base, to produce 1.00 L of a buffer that is 1.00 M in the weak base? grams potassium...