A laboratory test of a patient's blood reveals a hematocrit of 15% . microscopic examination of the blood also revea...
A laboratory test of a patient's blood reveals a
hematocrit of 15% . microscopic examination of the blood also
reveals several distorted and ruptured red blood cells.in addition,
the reticulocyte count is 2% . base on all of this findings, from
what disorder do you think the patient is suffering?
Homework Answers
Based on all of this findings, we can say that the patient is suffering from sickle cell anemia. Because, here 15% hematocrit means that RBC percentage is lower than the lower limit of normal level (40%). Microscopic examination of the blood also shows distorted and ruptured red blood cells. But the reticulocyte count is 2% which is normal (0.5-2.5%). So, there is no problem in production and release of RBC from bone marrow. But, RBC are not normal and healthy. These cells are mostly fragile and rupture prone.
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A laboratory test of a patient's blood reveals a hematocrit of 15% . microscopic examination of the blood also revea...
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patient?
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findings?
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Qn
based on the laboratory data what is a likely diagnosis for this
patient?
Question 2 How does this patient ‘s condition differ from the
conditions of other patients who might have similar laboratory
findings?
Case Study #1 udent health service. A A 20-year-old female college student with a sore throat is seen in the st throat swab is cultured with an intramuscular injection of pen and reported positive for group A β-hemolytic streptococci. She is treated icillin. Two weeks...
7. Bone marrow (a) Describe the characteristic appearance of the
bone marrow in this disorder.
(b) Discuss the mechanism responsible for these characteristic
bone marrow findings.
8. (a) Calculate the absolute reticulocyte count - show all your
work. Is it normal or abnormal?
(b) Based on your diagnosis, is this the result you would have
expected?
9. Schilling Test Review the results of the Schilling test below
and suggest the most likely diagnosis based on these findings.
Explain your answer....
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