Question

please help me to balance the following equations

Mg .Ca(NO)2 Mg Mg CUSO4 + Fe(NOs)3 Mg + SnCl Mg Zn(NO3)2 Mg + Sn Ca(NOs)2 Sn+ Sn + .CuSO4 Sn + Fe(NO)3 Sn+ MgSO Zn(NO3)2 _ Sn + Zn Ca(NO)2 Zn + CUSO4 Zn + Fe(NO3)3 Zn + MgsO Zn + SnCl Zn + TTTT T T1TT T

im having trouble foguiring out the coefficients and how to solve

Answer 1

Reactivity series is an arrangement of metals in the decreasing order of their reactivity (downwards). A metal placed higher in the reactivity series will be more reactive than the metal which is placed lower in the reactivity series. A metal higher in the reactivity series (more reactive metal) can displace a metal placed lower in the reactivity series (less reactive metal) from its compound or salt solution. This is called displacement reaction.

Mg

a. No reaction

MgCa NO3)2

Mg lies below Ca in the reactivity series, so it is less reactive than Ca. So it will not react with Ca(NO₃)₂.

b.

MgCuSO MgSO4Cu

Mg lies above Cu in the reactivity series, so it is more reactive than Cu. So it will displace Cu from CuSO₄ to form MgSO₄ and Cu as per the balanced chemical equation given above.

c.

MgFe(NO3)3Mg(NO3)2 Fe

Mg is above Fe in reactivity series, so it is more reactive than Fe. So Mg will displace Fe from Fe(NO₃)₃ to form Mg(NO₃)₂ and Fe. Now there are 3 NO₃ groups on left side in Fe(NO₃)₃ and 2 NO₃ groups on right side in Mg(NO₃)₃. So to balance it out write 2 as coefficient of Fe(NO₃)₃ and 3 as coefficient of Mg(NO₃)₂

Mg2Fe(NO3)33Mg(NO3)2 + Fe

Now there are 2 Fe on left and 1 on right side. Also there are 3 Mg on right and 1 on left. So to balance these out write 2 as coefficient of Fe on right and 3 as coefficient of Mg on left.

3Mg 2Fe(NO3)33Mg(NO3)22Fe

This is the balanced chemical equation.

d.

Mg SnCl M gCl2 + Sn

Mg lies above Sn in the reactivity series and is more reactive than Sn. So it will displace Sn from SnCl₄ to form MgCl₂ and Sn. Now there are 4 Cl on left and 2 on right, so to balance it out write 2 as coefficient of MgCl₂ and then to balance Mg on left write 2 as coefficient of Mg.

2MgSnCl42M GCL2 + Sn

This is a balanced chemical equation.

e.

MgZn(NO)2 Mg(NO3)2Zn

Mg is above Zn in reactivity series, so it is more reactive than Zn. So Mg will displace Zn from Zn(NO₃)₂ to form Mg(NO₃)₂ and Zn.

This is the balanced chemical equation.

Sn

a. Sn + Ca(NO₃)₂$\rightarrow$No reaction

As Sn is below Ca in the reactivity series, it is less reactive than Ca and cannot displace Ca from its compound. So no reaction takes place in this case.

b.

SnCuSO SnSOCu

As Sn is above Cu in the reactivity series, so it is more reactive than Cu and displace it from CuSO₄ to form SnSO₄ and Cu.

c. No reaction

SnFe(NO3)3 ->

As Sn is below Fe in the reactivity series, it is less reactive than Fe and cannot displace Fe from its compound. So no reaction takes place in this case.

d. $Sn+MgSO_4\rightarrow$ No reaction

As Sn is below Mg in the reactivity series, it is less reactive than Mg and cannot displace Mg from its compound. So no reaction takes place in this case.

e.$Sn+Zn(NO_3)_2\rightarrow$No reaction

As Sn is below Zn in the reactivity series, it is less reactive than Zn and cannot displace Zn from its compound. So no reaction takes place in this case.

Zn

a. No reaction

ZnCa(NO3)2 -+

Zn is below Ca in the reactivity series, so it is less reactive than Ca and can't displace Ca from its compound and hence no reaction takes place.

b. $Zn+CuSO_4\rightarrow ZnSO_4+Cu$

As Zn is above Cu in the reactivity series, it is more reactive than Cu and can displace Cu from its CuSO₄ to form ZnSO₄and Cu as per the balanced chemical equation above.

c. $Zn+Fe(NO_3)_3\rightarrow Zn(NO_3)_2+Fe$

Zn is above Fe in reactivity series, so it is more reactive than Fe. So Zn will displace Fe from Fe(NO₃)₃ to form Zn(NO₃)₂ and Fe. Now there are 3 NO₃ groups on left side in Fe(NO₃)₃ and 2 NO₃ groups on right side in Zn(NO₃)₃. So to balance it out write 2 as coefficient of Fe(NO₃)₃ and 3 as coefficient of Zn(NO₃)₂

$Zn+2Fe(NO_3)_3\rightarrow 3 Zn(NO_3)_2+Fe$

Now there are 2 Fe on left and 1 on right side. Also there are 3 Zn on right and 1 on left. So to balance these out write 2 as coefficient of Fe on right and 3 as coefficient of Zn on left.

$3Zn+2Fe(NO_3)_3\rightarrow 3 Zn(NO_3)_2+2Fe$

This is the balanced chemical equation.

d. $Zn+MgSO_4\rightarrow$ No reaction

As Zn is below Mg in the reactivity series, it is less reactive than Mg and cannot displace Mg from its compound. So no reaction takes place in this case.

e.  $Zn+SnCl_4\rightarrow ZnCl_2+Sn$

Zn lies above Sn in the reactivity series and is more reactive than Sn. So it will displace Sn from SnCl₄ to form ZnCl₂ and Sn. Now there are 4 Cl on left and 2 on right, so to balance it out write 2 as coefficient of ZnCl₂ and then to balance Zn on left write 2 as coefficient of Zn.

2ZnSnClA2ZnCl2+ Sn

This is a balanced chemical equation