Question

Part B (Mechanical Energy and Conservation of Energy) Problem B1: A block of mass m = 0.2kg is held against but not attached to a spring of so compressed by 20cm, as show below. When released, the block slides som the rough incline before coming to rest. but not attached to a spring of stiffness constant ka 50cm 20cm * = 0, Usp = 0 Low Ug = 0 Use mechanical energy for non-conservative force to find: 1) The force of friction when the bloc slides 50cm up. 2) The speed of the block just before as it leaves the spring. That is at x = 0.

Answer 1

som KSON Her om ugao om block Por To solve this problem we have to write Total energy at section 6 and 2 Total Energy at ③ = P. E of spring & P. E of block tk. Eg = ka't magdro + o Liche = 4 x 50X60-2) +ZxgSTA = 2580.04 = 15 Total Energy at = p. E og block noked = mxgx h Latar = 0.249.81 XOS Sin 35° =0.559 2 - no PE of spring work done by friction force = Total Energyall - Toled Energyal@ 1 -0.55 - o 455 This will be equal to 0.45= fx0.5 l d = friction f= 0.9N Scanned with CamScanner

on To find Speed of the block we have to write at xzo. at x=0 wille total Energy present T. Eat xao = P. Ef block t K E of block = mght imuz ,,2 Now, we can write Total Energy at 1 with will be equal to Total Energy at X=0 plus Work clone by friction force. -) I J = 0-2*9.81 X0.2 Sin35+ {xo 2xv10.980-2 Iv= 2.44 m/s) ** Please give like if you find Scannedhism solutien helpful. CamScanner