Solution Q1 comparison of mean of 4 types of service.
Solution is based on One-way ANOVA with unequal number of observations per group.
Final Results
ANOVA |
Table |
alpha |
0.05 |
|||
Source |
DF |
SS |
MS |
F |
Fcrit |
p-value |
Shift |
3 |
136317 |
45438.9 |
52.61132 |
2.845068 |
8.936E-14 |
Error |
39 |
33683 |
863.6717 |
|||
Total |
42 |
170000 |
4047.617 |
Since F > Fcrit or equivalently, since p-value < alpha, null hypothesis of equal means is rejected.
Hence, we conclude that the means of 4 types of Services are NOT equal. Answer
DONE
Details
Data
Ser 1 |
Ser 2 |
Ser 3 |
Ser 4 |
61 |
90 |
147 |
190 |
49 |
97 |
125 |
200 |
47 |
95 |
93 |
143 |
38 |
78 |
95 |
179 |
33 |
80 |
120 |
111 |
30 |
66 |
150 |
240 |
30 |
90 |
166 |
270 |
24 |
99 |
130 |
156 |
22 |
92 |
136 |
178 |
11 |
88 |
124 |
146 |
65 |
75 |
245 |
|
243 |
Calculations
alpha |
0.05 |
||
#treat |
4 |
||
n1 |
10 |
n4 |
12 |
n2 |
11 |
||
n3 |
10 |
||
n |
43 |
||
x1. |
410 |
x4. |
2301 |
x2. |
950 |
||
x3. |
1286 |
||
G = x.. |
4947 |
||
C |
569135.093 |
||
Sx1j^2 |
18070 |
Sx4j^2 |
467821 |
Sx2j^2 |
83108 |
||
Sx3j^2 |
170136 |
||
Sxij^2 |
739135 |
||
Sxi.^2/ni |
705451.8045 |
||
SST |
169999.907 |
||
SSR |
136316.7115 |
||
SSE |
33683.19545 |
DONE
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