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There are four theoretical mass ratios between the unknown compounds and the amount of chloride salt formed as a product...

There are four theoretical mass ratios between the unknown compounds and the amount of chloride salt formed as a product. These can be calculated prior to the experiment using Reactions 1 and 2. The reactions of the sodium salts are shown below; substituting potassium in for sodium gives the reactions of the potassium salts.

2NaHCO3(s) → Na2CO3(s) + H2O(g) + CO2(g) (1)

Na2CO3(s) + 2H+(aq) + 2Cl−(aq) → 2NaCl(s) + H2O(l) + CO2(g) (2)

Considering the overall reaction from the original hydrogen carbonate in Reaction 1 to the chloride salt in Reaction 2, complete the following mole ratios and mass ratios for the two possible hydrogen carbonates. 1 mole NaHCO3 → __________ moles NaCl __________ g NaHCO3 → __________ g NaCl mass ratio __________:1 (NaCl to NaHCO3) 1 mole KHCO3 → __________ moles KCl __________ g KHCO3 → __________ g KCl mass ratio __________:1 (KCl to KHCO3)

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Answer #1

2 NaHCO3 (s ....(1 Na2CO3(s)H2O(g) + CO2(g) Na2CO(s)2H (aq) 2C1 (aq)»2NaCl(s) +H2O (l)CO2(g) ....(2) Molar weight (g/mol) Mol1 mole KHCO3»1 moles KCI 100.115g KHCO 74.551g KC 100.115 g KHCO3 74.551g KCl 1 g KHCO = (74.551/100.115) g KCl =0.7446 g KCI

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