Question

62. A certain kind of glass has an index of refraction of 1.65 for blue light of wavelength 430 nm and an index of 1.615 for red light of wavelength 680 nm. If a beam containing these two colors is incident at an angle of 30° on a piece of this glass, what is the angle between the two beams inside the glass?

Answer 1

na 2. loc de mundimin o le aiy for led lighet, hue= 1.615. From Shell's law, Sin 0; her Sinop - one: angle of Sinop het refraction for 2 Sin 30 Since =2 sin ore a 0.5 = 0.31 For Blue light, 128= 1.65 From Shell's law, fino; = 128 Sinar ore Angle of retraction for Blue. Sinero - => sin De de ene 0.303 Op = fin-1 (0.303) = 17.63°/

PB 3.0 19.6706 > 16.030 Blue inside the glass Angle b/w two beams 18.03 - 19.63" = 0.40