Question

G(s)=Kc*(1+tD*s+1/(tI*s)), Kc=10, tD=100, tI=1, plot the amplitude ratio and phase bode plot.

Answer 1

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dirRenet Valuu of w and an tai the AR and Phan A Phax an ) S1.9 AR 9999 000 989.9y ts.ob 999 90.00 999-94 ixca)

phase W 2 0.001 -89.94 3 -90.57 1 4 10 -90.05 -90 1000 6 -89.8454 7 1200 1000 400 800 200 600 9 -90.0265 10 11 90.2077 12 Series1 13 Log. (Series1) 14 -90.3888 15 16 17 -90.57 18 19 -90.7511 20 21 22 23 24 25 Sheet3 Sheet Sheet1 Ready RNR

Clipboard Font Alignment P12 A B D H E 1 AR W 2 0.001 9999000 3 989.94 4 10 999 5 1000 999.94 12000000 7 10000000 10 8000000 11 6000000 12 Series1 13 4000000 Log. (Series1) 14 2000000 15 16 0 17 200 1000 1200 400 600 800 -2000000 19 -4000000 20 21 22 24 25 K Sheet2 Sheet1 Sheet3 Ready 8EFRE3
we can substitute the values of Kc,ti and td to obtain G(S).

We can substitute s=Jw and rationalize the equation.

Then it reduces in the form of complex equation of the form

a+ib the Amplitude ratio is given by sqrt(a^2+b^2 )

phase angle is given by tan^-1 b/a.

After getting this the value of the w is carried and the graphs are made which are known as bode plots.

Thank you