Figure 1 shows a parallel chord truss of span 4 m and depth 3 m. Take E =200 kN/mm2. The solution follow the member lab...
20:51 43601_Assignm... QQ. 18% ; Question 1 CORRECTED [25 MARKS] Figure 1 shows a parallel chord truss of span 4 m and depth 3 m. Take E =200 kN/mm². The tension members all have a cross-sectional area of 2000 mmand compression members have an area of 2500 mm. Find the vertical deflection and horizontal deflection of the joint A due to a horizontal (-) point load of 125 kN acting at A, and a vertical point load of 50 kN...
Question 4 The plane truss is subjected to a load as shown in Figure 4. Take E = 200 GPa and cross sectional areas of members 1, 2 and 3 as 150, 250 and 200 mm2 respectively a) Assemble the upper triangular part of the global stiffness matrix for the truss. b) Determine the horizontal and vertical displacements at node 4. c) Calculate the forces in each member of the truss. (25 marks) 20 kN 3 600 4 3 1.5m...
15 m B- Question 3: Each member of the truss shown is made of steel (E- 2 1 0 GPa ) and has a cross-sectional area of A If you know that the joint E subjected to horizontal load 16-kN Determine: .The horizontal displacement of point E . The vertical displacement of point C. 400 mm2 0.8m 16 KN 15 m B- Question 3: Each member of the truss shown is made of steel (E- 2 1 0 GPa )...
2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for the three truss vertical downward force P(kN) is a members. The cross sectional area of each of the truss members is indicated below and expressed in terms of a constant A. By using the stiffness method: (a) Compute the reduced stiffness matrix Kg [5 marks [10 marks (b) Calculate the global displacements of node 4 in terms of P,...
2. Use the virtual work method to determine the horizontal deflection at joint H of the truss shown in Figure 2 G (1500 mm2) H 4 m (1500 (1500 150 kN> 4 m (1500 mm2) (1500 2 m E-2x10S MPa Im Figure 2 2. Use the virtual work method to determine the horizontal deflection at joint H of the truss shown in Figure 2 G (1500 mm2) H 4 m (1500 (1500 150 kN> 4 m (1500 mm2) (1500 2...
The plane truss is subjected to a load as shown in Figure 4. Take E = 200 GPa and cross sectional areas of members 1, 2 and 3 as 150, 250 and 200 mm2 respectively a) Assemble the upper triangular part of the global stiffness matrix for the truss b) Determine the horizontal and vertical displacements at node 4 c) Calculate the forces in each member of the truss. (25 marks) 20 kN 3 60° 4 1.5m 2 2 20m...
Consider the truss shown in (Figure 1). Suppose that F-4 kN and Fa = 9 kN 1 of 1 Figure 4 m 4 m ▼ Part A Determine the force in member BE and state if the member is in tension or compression Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. Part B Determine the force in member EF and...
(3pts): The truss is constructed of A36 steel (E -2 a cross-sectional area of 250 mm2. Answer the following s 300 Clbe wna -250 MES, AI 00 G Pa and O, 250 MPa). All truss members have (a) Determine the normal stress and strain in member CD. (b) The support at joint D uses a pin placed in double shear. The pin diameter is 20 mm Determine the average shear stress acting in the pin. 50 kN 50 kN 25...
Problem 1 Determine the force in each member of the truss and state if the members are in tension or compression. (Please use Method of Joint) Given: P, = 500 lb P, = 1500 lb a=10 ft b=10 ft Problem 2 Problem 3 Determine the force in members CD, CF, and GF of the truss. State if these members are in tension or compression. (Please use Method of Section) 5 kN 4 kN 4 kN 3 kN 2 kN (...
The cross-sectional area of each member of the truss shown in the figure is 4 = 400 mm and E = 200 GPa. (a) Determine the vertical displacement of joint Cif a 4-KN force is applied to the truss at C. (b) If no loads act on the truss, what would be the vertical displacement of joint C if member AB were 5 mm too short? (c) If 4 kN force and fabrication error are both accounted, what would be...