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Question 9 (1 point) The reaction is measured at three temperatures and the following rate constants have been determined: Ra
300 4.00 x 100 319 2.00 x 10-2 What would you graph if you needed to extract the activation energy from the slope of the grap
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Answer #1

The relation between K and T is:

K = A*e^(-Ea/RT)

taking ln on both sides, above expression becomes,

ln K = ln A - Ea/RT

So, slope between ln K and 1/T will have a value of -Ea/R and y intercept is ln A

So, we need graph between ln K and 1/T

ln K is y axis

1/T is x axis

Answer: optioon 2

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