Homework Answers
| Employed full time | Not Employed full time | Marginal Row Totals | |
| Earned at least a high school diploma | 52 | 40 | 92 |
| Did not Earn a high school diploma | 30 | 35 | 65 |
| Marginal Column Totals | 82 | 75 | 157 (Grand Total) |
Expected cell counts
E11 = (92*82)/157 = 48.05 , E12 = 92*75/157 = 43.95 , E21 = 65*82/157 = 33.95 , E22 = 65*75/157 = 31.05
| Employed full time | Not Employed full time | Marginal Row Totals | |
| Earned at least a high school diploma | 52 (48.05) | 40 (43.95) | 92 |
| Did not Earn a high school diploma | 30 (33.95) | 35 (31.05) | 65 |
| Marginal Column Totals | 82 | 75 | 157 (Grand Total) |
the values in () in the above table are the Expected counts.
Hypothesis:
H0 : employment status and levels of education are independent of each other.
H1 : employment status and levels of education are not independent of each other.
test statistic 
= (52 - 48.05)2/48.05 + .....+ (35 -
31.05)2/31.05 = 1.641
degrees of freedom = (r-1)(c-1) = (2-1)(2-1) = 1
r = number of rows = 2
c = number of columns = 2
p-vlaue = 0.2001.
level of significance alpha = 0.05
Since p-value is greater than alpha we fail to reject null hypothesis and there is no significant evidence to conclude that the "employment status and levels of education are independent of each other."
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