Question

3, At 25°C, to charge a Zn electrode in a 0.044 M ZnSO4 solution. The charging current is 0.03 A/cm2, the potential is -1.013 V. The charging condition is a highly polarizable condition (I »>iº). Charge transfer =-0.763 V coefficient a=0.45 and . Calculate the exchange current, 10. (hint: Calculate electrode potential using Nernst equation, then use the Bulter-Volmer equation at highly polarizable condition). E 211

Answer 1

Ans Given 1.013 V RE 3.214 Jmol -0.63 V T= (१৪-।S ८ 90.044 M 4e 0-03 Aon We kmow dhat Electrode potential (E)- E- R T ४ 314 X 1१४-{8 E= Co.o4) e) (16560) 0.86 B using Bulterrolmer euadton at polasizable Candidio as The highly fo lows CE-Ea) R.T n 2x9650o O.o o.03 3-314 x 218.15 o.0019 24 A/cm i The Exchanye of lurvent i0-002y c