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Apps Image result for en... My Notes O Ask Your Teacher 7 4 points 0/4 Submissions Used The table below gives data on moistur

13.1, 12.7,13.2 12.1 12.3 subsampii-c 12.6 , subsamp12-c( subsamp13-c( 13.4 , 13.3, 12.0 12.9 subsamp14-c( 13.5, 12.4 13.0, 1

#Create x-bar s chart qcc(moisture_content, type xbar) Construct a control chart with an estimated center line and limits b

Just provide a proper and easy to read, correct answer.

Apps Image result for en... My Notes O Ask Your Teacher 7 4 points 0/4 Submissions Used The table below gives data on moisture content for specimens of a certain type of fabric. Copy the data into R to construct an x-bar chart. #Sample No. subsamp1-c( subsamp2=c Moisture-Content Observations 12.3 12.1, 13.1, 13.0, 13.0 ) 13.3, 12.8, 12.6, 12.9 ) subsamp4=ct subsamp5-cl subsamp6-c subsamp7=c( subsamp8-c 13.2 13.0 13.0 12.6 13.7 12.4 13.3 12.0) 13.1 12.4 13.2) 12.5) 13.1 12.8 12.3 13.9 13.4 14.4 12.4 12.4 . 12.6 12.8 13.5, 13.9 12.2 4 12.2, 13.7 12.5 subsamp10-c( subsamp11-c( subsamp12-c ( 13.5 subsamp13=c( subsamp14-c subsamp15-c( 12.3 12.8 subsamp16-c( 12.6 13.4 12.6 13:1 12.7 13.2 12.3 . 13.1 12.9 ) 12.9 13.1) 13.6 13.4) 12.8 13.5) 13.2 13.4 13.0 13.9 12.1 12.8 13.4 13.3 12.0 . 13.5 12.4 13.0, 13.0. 12.1 ubea 13 0 subsamp19-c subsamp20-ct subsamp21-c 12.6 12.8 12.7, subsamp22-c( 12.7, 13.4 12.1 12.4 13.2 13.0 14.0 12.7 12.4 12.4, 13.9 12.8) 13.4 13.0) 13.2 13.4) # Combine the rows of sub samples into a data frame. #This structures data appropriately for control chart functions. moisture_content data.frame(rbind(subsamp1,subsamp2,subsamp3,subsamp4 subsamp5,subsamp6, subsamp7,subsamp8,subsamp9, subsamp15,subsamp16,subsamp17,subsamp18 subsamp10,subsamp11,subsamp12,subsamp13,subsamp14, ,subsamp19,subsamp20,subsamp21,subsamp22)) # Check out the data frame moisture_content # Check subgroup means rowMeans(moisture content) If you have not already, install the install.packages("qcc") qcc package in R. Skip this line otherwise. # Open the library of commands library("qcc") from the qcc package.
13.1, 12.7,13.2 12.1 12.3 subsampii-c 12.6 , subsamp12-c( subsamp13-c( 13.4 , 13.3, 12.0 12.9 subsamp14-c( 13.5, 12.4 13.0, 13.6 subsamp15-c 13.5 12.8 13.1 12.9 13.1 13.4 12.6 13 4 12 13.4 subsamp17=C( 12.1, 12.7, 13.4, 13.0 subsamp18-C( 13.0, 12.8 13.0, 13.3 subsamp19-c 12.4 13.2 , subsamp20-c 12.7, 12.4 subsamp21-c 12.6, 12.8, 12.7,13.4 subsamp22-c 12.7, 13.4, 13.9 13.1 13.0 14.0 12.4 13.9 13.1 12.8) 13.0 12.1 13.2 13.4 1 #Combine the rows of sub samples into a data frame. #This structures data appropriately for control chart functions. moisture_content data.frame(rbind(subsamp1,subsamp2,subsamp3,subsamp4,subsamp5,subsamp6, subsamp7,subsamp8, subsamp9,subsamp10,subsamp11,subsamp12,subsamp13,subsamp14, subsamp15,subsamp16,subsamp17,subsamp18,subsamp19,subsamp20,subsamp21,subsamp22)) #Check out the data frame moisture_content #Check subgroup means rowMeans(moisture_content) you have not already, install the gcc package in R. Skip this line otherwise. install.packages("qcc") Open the library of commands from the qcc package. library("qcc") # Create x-bar chart qcc(moisture_content, type "xbar) Construct a control chart with an estimated center line (Round your answers to one decimal place.) and limits based on using the sample standard deviations to estimate a LCL- UCL= 14.0 14.0 UCL 13.5 13.5 UCL
#Create x-bar s chart qcc(moisture_content, type "xbar") Construct a control chart with an estimated center line and limits based on using the sample standard deviations to estimate a. (Round your answers to one decimal place.) LCL UCL 14.0 14.0 UCL 13.5 13.5 UCL 13.0 13.0 12.5 12.5F LCL LCL 12.0 Sample No. 12.0 Sample No. 5 10 15 20 5 10 15 20 X 14.0r 14.0 UCL 13.5 13.5 UCL 13.0 13.0 12.5 12.5 LCL LCL 12.0 0 Sample No. 12.0 0 Sample No. 5 10 15 20 10 15 20 Is there any evidence that the process is out of control? All points are between the control limits, so the process appears to be out of control. Most points are between the control limits, so the process appears to be in control. O At least one value is not between these limits, so the process appears to be in control. O At least one value is not between these limits, so the process appears to be out of control. All points are between the control limits, so the process appears to be in control. O Show My Work (optional) Type here to search
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from fia.O X centel line -12.9 LCL LOwer centrel ioe-12.2 UCLE Uppe centrel Aoe 13 7 All paint appears to be cantallimits Sofrom fig 12 9 12.2 LCL 13 7 UCL ame bes conhrol imid So e n control all points process to be tram fig 1 2 12.6 LCL 13. 3 All

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