J's | JO W R Ca) M-100DV/V Rs=Rid=00 Tor = 1KR RI =10KR R2- POK2 Yol...
J's | JO W R Ca) M-100DV/V Rs=Rid=00 Tor = 1KR RI =10KR R2- POK2 Yol -20k Frand A.RERO WE
M w R6 V1 w R7 For the circuit in the figure above, Vi=12 V. Ri=50, R2 = 10 . R3 = 8 0 R4 = 2 0 Rs=3 R6 = 70, and Ry=90. What are the currents through and potentials across each of the resistors?
Will leave a line for solving :) Problem IIIA A pair of resistors RI and R2 share the wattage of W watts totally dissipated by them in the ccit of Figure. III-A a. Determine the currents I and I2 in terms of Ri, R. and W. (Ans: I(WR)2 x [R (RI+Ro)]A; Hint: Use current division theorenm b. Suppose Ri.30 and R23, denote the values of Ri and R respectively at room temperature 30 C. These elements are made of two...
Riz Ga tor 2.2 kN > w 5.6 k 2023 R4Z 10.0 k 12 +12 V R2 Z 4.7 k12 Figure 10–3 As a check on your solution of the circuit in Figure 10-3, apply Kirchhoff's voltage law to each of two separate paths around the circuit. Show the application of the law. 3. Show the application of Kirchhoff's current law to the junction of R, and Rs of the circuit in Figure 10-3.
answer (B) only show all work Problem IIIA A pair of resistors Ri and R2 share the wattage of W watts totally dissipated by them in the circuit of Figure. III-A a. Determine the currents ll and 12 in terms of Ri, R2, and W. (Ans: 1,-(WRP)12 × [R2/(RI+R2)] A ) Hint: Use current division theorem b. Suppose R1-30 and R2-30, denote the values of R, and R respectively at room temperature 30°C. These elements are made of two different...
(MAS BR 1000 w 4000 w 30 Ri 40 R 2000 2000 (m) Figure Q4(a) Figure Q4(b) Calculate the average and the effective current is ) as indicated in Figure Q4 (a). (marks) (6) Based on the answer in Q4 (a), determine the effective current flows through Rs. (4 marks) Calculate the average power absorbed by Rs. (2 marks) If the input current is replaced with the sinusoidal wave having a peak-to-peak value of 160 mA and frequency of 1...
V.+w Operation in the triode reglon Condition v. e Wov 20 Vos uov os os-V (2) p V, so onl+Pala Characteristics Same relationships as for NMOS trasistos tCharacteristics: a CuGs- V,) ®os- } ip.C Replace .and NA with p,,and Nprespectively. V.V V, and yare negative. 2 wov ps For vos 2( -V) e Conditions for operation in the triode region ip lvi Q1. (10 points) For the following configuration of the given figure below, with the following parameters: VDD= +10...
For the following design L1-2H C1-0.05F R1.4Ω R2-4Ω C2-0.05P L2-2H Va 4cos(10t+90°)V vb-4cos( 10t+90"N R4-4Ω R6:2Ω RS-4Ω Vc-4cos(20t+90jv vds4cos( 10t+60ον (Remember that i) w is given in rad/sec, ii) the above circuits have different Impedances for different frequencies, ii) we replace the shorted voltage power supplies with a short circuit, iV) with atjb the rectangular form and Ad the polar form we have a-Acos(8), b-Asin(θ), A-: va2+1,7 , θ= tan-l (4)if a > 0, θ= 180-tan-IL) if a <0) a)...