Question

8. Calculate AS, ASgurr, and Astot for the process H2O(s) → H2O(l) when the surrounding are at -10°C. Use AHfus[H2O]=6.01 kJ/
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Answer #1

H2O (s) To H2O (l)

T = -10oC

Convert temperature to kelvin

Temperature in K = (273.15+(-10)) = 263.15 K

Δ H = 6.01 kJ/mol

Convert 6.01 KJ/ mol to J/mol:

1 kJ = 103 J

6.01 x 103 J/Mol = 6010 J/K

Step 1: Calculate AS or A System AS-- shfus J/K ASE-9930J/K AS = 22.00 J/K 273.15 Step 2: Calculate A S surrounding A Ssurrou

Since Δ Stotal = -ve hence the process is non-spontaneous.

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