Question

05 Question (4 points) Titanium (0 = 6.94 x 10-19 )) and silicon (0) = 7.77 x 10-19 ) surfaces are irradiated with UV radiation with a wavelength of 229 nm. 4th attempt Part 1 (2 points) Il See Periodic Table O Sec What is the wavelength of the electrons emitted by the titanium surface? nm

Answer 1

1)

Given:

lambda = 2.29*10^-7 m

use:

E = h*c/lambda

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2.29*10^-7 m)

= 8.68*10^-19 J

Use:

KE of electron = E - Eo

= 8.68*10^-19 J - 6.94*10^-19 J

= 1.74*10^-19 J

Now use:

KE = 0.5*m*v^2

1.74*10^-19 J = 0.5*(9.11*10^-31 Kg)*v^2

v^2 = 3.82*10^11

v = 6.18*10^5 m/s

so, we have:

v = 6.18*10^5 m/s

mass, m = 9.11*10^-31 Kg

use:

lambda = h / (m*v)

lambda = (6.626*10^-34) / (9.11*10^-31*6.18*10^5)

lambda = 1.177*10^-9 m

lambda = 1.177 nm

Answer: 1.18 nm