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Answer is: (a) 1 − 0.091 cos(104 t + 0.011)

12V Vcc 11k a(t) + UB 1k 10HF UE k NL 2N k Figure 5: Circuit for Questions 12-15 Question 13. (2 marks) Consider the circuit

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12V ر 1 11k علد، Vp اس (~ ) l/م ه و ه باا أ ن؟ s(4) Cos (ot) v جل Vp (de) ر 1 V حج fAC Anaysis َ لا EP ج ) دچ مدعا ٥/۴ }ءك(o)6254 Cet(1tto.61t Cattt t 0 2 19 ( 0.02 19| mA Col04t V9 4K

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