4)
Lets number the reaction as 0, 1, 2, 3 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = -0.5 * (reaction 1) -0.5 * (reaction 2) -0.25 * (reaction 3)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = -0.5 * ΔHo rxn(reaction 1) -0.5 * ΔHo rxn(reaction 2) -0.25 * ΔHo rxn(reaction 3)
= -0.5 * (47.5) -0.5 * (210.0) -0.25 * (-805.0)
= 72.5 KJ
Answer: 72.5 KJ
Only 1 question at a time please
0.00595mal 3 0948 22322- UL 2. ole 11284) Calculate the standard enthalpy of the reaction Hz(g)...
problem is together.
3. Calculate the enthalpy of formation of carbon dioxide in the following reaction: C(s) + O2(g) - CO, (g) Use the following equations: a) H2O(l) → H2(g) + 2O2(g) AH°-= +285.8 kJ/mol b) C2H6(g) → 2C (s) + 3H2(g) AH'= +84.7 kJ/mol c) 2CO2 (g) +3H2O (1) C2H6(g) + (7/2) O2(g) AH°F = +1560.7 kJ/mol
Calculate standard free energy change using AHp and So values. Consider the reaction 2NH3(8) + 3N20(g)—__4N2(g) + 3H2O(g) Calculate the standard free energy change for this reaction at 25°C from AH°rxn and AS°rxn- AGºrxn = kJ/mol
Example Problem Calculate the enthalpy (AH°, ) of combustion of Benzene, CH6. rxn C6H615/2 O2 (8)6CO2 (g) + 3H2O AH°, [C6H6= 49.0 kl/mol AH°% [CO2(@)= -393 .5 kJ/mol AHO, [H20 = -285.8 kl/mol AH', [O2@= 0 kl/mol
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1
7. Calculate the enthalpy of change for the following chemical reaction: CS,(0) + 3 O.(g) CO.(g) + 2 SO.(g) Use the following information: C(s) +0(g) - CO.(g); AH, 393.5 kJ/mol S(s) + O2(g)--S0(g); ΔΗ, ,--296.8 kJ/mol C(s) kJ/mol 296.8 kJ/molCS); 2 S(s) 87.9
2. Calculate the standard reaction enthalpy for the following reaction: Pb(s) + 1/2O2(g) → PbO(s) Given: PbO(s) + C(s, graphite) → Pb(s) + CO(g) 2 C(s, graphite) + O2(g) → 2 CO(g) AH = 106.8 kJ AH = -221.0 kJ
The following questions refer to the following reaction at 25°C and 1 atm. 2Fe(s) + (3/2)O2(g) + 3H2O(1) ► 2Fe(OH)3(3) AH = -789 kJ/mol Substance Fe(OH)3(S) Fe(s) O2(g) H2O(1) Sº (J/mol K) 107 27 205 70 7. Determine ASgurr for the reaction (in kJ/mol K) A) 3.14 B) 0.937 C) 0.378 D) 1.31 E) 2.65 8. Determine ASuniv for the reaction (in kJ/mol K) A) 0.23 B) 2.3 C) 0.36 D) 2.8 E) 3.6
Calculate AH for the reaction 2 KCIO: (s) → 2 KCl (s) + 3 O2 (g) ΔH°r of KCIO3 (s) = -397.7 kJ/mol ΔH°r of KCI (s) = -436.5 kJ/mol
2. Calculate the enthalpy for the reaction below at standard
conditions using Appendix G in your textbook. [Report the answer to
three sig fig, without unit labels, and using +/- signs to indicate
if the reaction is endo- or exothermic.] 2 Al(s) + Fe2O3(s) -->
Al2O3(s) + 2 Fe(s)
Substance AH (kJ mol-) AG; (kJ mol-1) Sº (JK-1 mol-2) aluminum 0 0 28.3 324.4 285.7 164.54 -531 -485 -321.7 Al(s) Al(g) Al3+ (aq) Al2O3(s) AlF3(s) AICI3(s) AlCl3.6H2O(s) -1676 -1582 50.92...
Calculate the standard enthalpy change for the following reaction at 25 °C. MgCl, (s)+H,O)MgO(s)+2 HCI(g) AH; values can be found in this table of thermodynamic values. AH= kJ/mol