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m Relative Intensity - Which compound gives rise to the MS below? HN 58 100 N.N-dimethylethylamine 80 60 20 TE 65 70 75 10 15
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Answer #1

N,N-dimethylethylamine will give rise to the spectrum.

These peaks arise due to following fragmentation pattern,

CH3 has a molecular weight of 12+3=15 so, when a methyl fragment gets released the m/z value decreases by 15.

When CH3CH2 fragment gets released the m/z value decreases by 15+14=19. (Molecular weight of CH3 fragment is 15 and CH2 fragment is 14.)

maleculor 1on peak at 3 e H3 M/2-73 HyC NCH2CCH HyCteet N2 peak at S8 1 CHs 73-15 peak at 44 N 1 CH3 CH2 73-29

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