Question

a block of mass is suspended from an ideal spring with force constant k

ideal spring with force constant k-0.200 N/m. The mass is pushed 15.0 cm below its equilibrium position and then given $1.80 kg is suspended from an ideal spring with force constant k = 0.200 downward (watch signs). its equilibrium position and then given an initial speed of 0.300 m/s directed What is the period of the resultine SHM of the block? Show work. (15 points) "pward direction as a positive axis, the resulting motion of the block can be written as Yay.cos(of+) o in mi in s). Find the values of o, y, and 6. Show work. (15 points)

Answer 1

By substitution of the value you will get pressure P1 = 10.6 Pa and height H = 95.87m.

a Extension of spring by velocity, & mv² = 28x² » 3w=( v J 119 x 0.3 = 0.9 maguem so Amplitude n= 31+710 = 15 +50= 105 cm - login Period of oscillation : 20 m = 20 677 second 7 - Yousw2+0) wa Jim Joie sa of radis = 0.33 Rod Is 16.65 1106 ® Im = A= 105m Yr Ym cos(wxtd) s 15 = 105 cas (wo)+4) o los de los = 4, 10-01-78° Ø using continuity equation Alzzan, A=2m? a = 5x10-3 m², N, 250 ml = 0.5ml V = nu = 5*103) XO-551-25X103 mo 6 P: rv, a f = e = 2652 2530N @ Using Bessoall's eqn between pump and Topofweler os TP = parim + ļ ??) $3h OD P, q), FPTP, = avel * Purmerno Thota Parlouis Jogurtiny