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xplanation For homogeneous equilibria, Kc is the ratio of product to reactant concentration aised to their respective stoichi
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Answer #1

2BrCl (g) \to Br2 (g) + Cl2 (g). (1)

Kc1 = Br2]C12 [BrCl] = 377

For the reaction

Br2 (g) + Cl2 (g) \to 2BrCl (g) (2)

Now,

Kc2 =  [BrCl2 [Br2] [C12] = \frac{1}{Kc1} = \frac{1}{377} = 0.00265.

Hence value of equilibrium constant (Kc) for reaction 2 = 0.00265 .

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