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let X have a continuous uniform distribution with a minimum value of 120 and a max...

let X have a continuous uniform distribution with a minimum value of 120 and a max value of 160 what is the 82nd percentile?

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Answer #1

Solution :

Given that,

a = 120

b = 160

PERCENTILE

= a + (b - a)p

= 120 + (160- 120)0.82

=152.8

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