we have:
[A]o = 0.29 M
43 % is complete.
So, remaining is 57 %
[A] = 57 * of 0.29 M
= 57*0.29/100
= 0.1653 M
t = 64.5 min
use integrated rate law for 2nd order reaction
1/[A] = 1/[A]o + k*t
1/(0.1653) = 1/(0.29) + k*64.5
6.05 = 3.448 +k*64.5
k*64.5 = 2.601
k = 4.033*10^-2 M-1.min-1
Given:
k = 4.033*10^-2 M-1.min-1
use relation between rate constant and half life of 2nd order reaction
t1/2 = 1/([A]o*k)
= 1/(0.29*4.033*10^-2)
= 85.5 min
Answer: 85.5 min
The reaction The reactionA -> B+C is second order with respect to A. When [A]0= 0.290...
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