Concept :- we first find the time taken by the
electron to cross the plate. Then we use that to find the
acceleration using kinematics equation, Then we use Newton's law of
motion and force on charged particle in an electric field to find E
as follows, ***************************************************************************************************
This concludes the answers. If there is any mistake,
let me know immediately and I will fix
it....
2. A parallel plate capacitor is formed with two plates separated by 5.00 mm as shown...
A parallel plate capacitor is formed with two plates separated
by 5.00 mm as shown in Figure 1. Each plate is a 10.0 cm X 10.0 cm
square. We do not know the charge on the plates. An electron beam
is shot in from one edge of the capacitor. It enters the capacitor
very close (call it 0 mm) from the top plate and travelling
parallel to the plates. The electrons in the beam are moving at
1.50 × 107...
A parallel plate capacitor is formed with two plates separated by 5.00 mm as shown in Figure 1. Each plate is a 10.0 cm X 10.0 cm square. We do not know the charge on the plates. An electron beam is shot in from one edge of the capacitor. It enters the capacitor very close (call it 0 mm) from the top plate and travelling parallel to the plates. The electrons in the beam are moving at 1.50 × 107...
A parallel-plate capacitor consists of two plates, each with an area of 36 cm2, separated by 9.0 mm. The charge on the capacitor is 2.1 nC. An electron is released from rest next to the negative plate. How long does it take for the electron to reach the positive plate? Exoress your answer in ns.
A parallel-plate capacitor consists of two plates, each with an area of 36 cm2, separated by 9.0 mm. The charge on the capacitor is 2.1 nC. An electron is released from rest next to the negative plate. How long does it take for the electron to reach the positive plate? Express your answer in ns.
A parallel-plate capacitor consists of two plates, each with an area of 21 cm^2 separated by 3.0 mm. The charge on the capacitor is 5.8 nC. A proton is released from rest next to the positive plate. How long does it take for the proton to reach the negative plate?
An air-filled parallel-plate capacitor has plates of area 2.80 cm^2 separated by 2.50 mm. The capacitor is connected to a(n) 17.0 V battery. Find the value of its capacitance. _____ pF What is the charge on the capacitor? ______ pC What is the magnitude of the uniform electric field between the plates ___________ N/C
Two parallel plates (2 cm by 2.5 cm) generate an electric field. An electron is fired with a speed of 4.4 x 107 m/s between the plates, perpendicular to the electric field direction. (See figure). The plates are charged to +/- 25 nC. a. Which plate must be positive, the top or the bottom plate? b. If the plates are 2 cm long in the direction the electron is travelling, the electron's trajectory when it leaves the plates will be...
A parallel-plate capacitor
consists of two plates, each with an area of 29 cm2 separated by
3.0 mm. The charge on the capacitor is 9.8 nC . A proton is
released from rest next to the positive plate. How long does it
take for the proton to reach the negative plate?
A parallel-plate capacitor consists of two plates, each with an area of 29 cm2 separated by 3.0 mm. The charge on the capacitor is 9.8 nC. A proton is...
The circular plates of a parallel-plate capacitor are 6.00 cm in diameter and are spaced 5.00 mm apart. They are charged by transferring 1.00 x 10" electrons from one plate to the other. What is the electric potential difference between the plates? (A) (B) 2,540 V 2,970 V 3,200 V 3,880 V 4,350 V (D) (E)
A parallel-plate capacitor consists of two plates, each with an area of 25cm2 separated by 3.0 mm. The charge on the capacitor is 9.3nC . A proton is released from rest next to the positive plate. How long does it take for the proton to reach the negative plate?