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09.06 F9.08 os 9.22 12.74 42.04 k 16.82 12, 08 6 roller Find E at point 6 of 90 KN darunward. moment of every paint (member!

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Answer #1

There are no horizontal forces only vertical force F = 90 kN at G.

we find reactions at A and L , supports Ay and Ly

take moments about A.

\Sigma Ma = Ly* 54 -90*27 =0

Ly = 45 kN

\Sigma Fy = Ay + Ly - 90 kN =0

Ay = 45 kN

Moment of about C

Mc = -18*90 = -1620 kN-m

about E

Me = -9 *90 = -810 kN-m

about G : Mg = 0*90 = 0

about H : Mh = 9*90 = 810 kN-m

about J ; Mj = 18*90 = 18 *90 = 1620 kN-m

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