Question

can anyone please write an explanation as well when answering? thank you for your assistance

R Vin nwww Vot) Take a square wave signal from Function Generator for Vin through AO 0 port. Then set Vn and Vas to Al 0 and Al 1 respectively in order to observe the input and output waveform using oscilloscope. Vary the frequency of the square wave input according to the values shown in the table below. Then, observe the amplitude of the output signal, Ve (pp) Take screenshots of Ve and Vin waveform, keeping them in the same window for all the frequencies. Attach the screenshots for all frequencies along with the reports. Square Wave Settings Duty Cycle Theoretical Time Constant DC Vo pe) C Frequency (Hz) Amplitude Offset rRC 1/10r 1/5r 1/2r 1/r 2/rm 0.5 V 50% 1.00 Vpp 1 kn 0.1 uF Explanaticg a Vin b e C Take a sine wave signal from Function Generator for Vn through AO0 port. Then set Ve and Va/ Ved Vas to Al 0 and Al 1, respectively, in order to observe the waveforms in oscilloscope. Tum Ratio (d-e): (a-b) Ve V (RMS) V Va (p-p) (RMS) Turn Ratio (d-e): (b-c) Vab Vab Turn Ratio (d-e): (a-c) Vn (RMS) (p-p) (RMS) (p-p) 2 Vpp @ 1kHz Explanation: Awww mwww

Answer 1

R	C	Time constant RC	Square wave settings
1kOhm	o.1µF	10-4	Amplitude	Duty cycle	DC offset	Frequency	Vo pp
			1Vpp	50%	0.5V	1/10RC	1.97V
						1/5RC	1.696V
						1/2RC	0.923
						1/RC	0.489
						2/RC	0.248

Explanation ,

The given circuit is an integrator circuit

Vo1/RC Vindt

If input to an integrator is square wave output will be triangular

Frequency 1kHz (1/10RC)

vou 0.0364 ma 037 0.0375 L

Frequency 2kHz (1/5RC)

1.5 05 05 0.0395 0.0355 0,036 0.0365 0.037 0,0375 0.038 0,0385 0,039 0.04 Vout 1.5 05 0.5 00365 0.039 0,0355 0.036 D.037 0.0375 0,038 0,0385 0.0395 D.D4 Offset-D

Frequency 5kHz (1/2RC)

Vin 6.8 6.4 6.8 10 0.5 64 6 F 6.8 10- Offset-D

Frequency 10kHz (1/RC)

Vin 6.9 05 6.8 6.7 66 6.5 x 10년 6.4 Vout 06 0.6 o 4 6.9 6 5 0z 6.6 6 4 65 10- Offset D

Frequency 20kHz (2/RC)

Vin 0.5 05 6. 67 6 3 64 6 5 10 Vout 0.65 06 A 0.55 0.5 In 45 0.4 0.35 WWWWwW 6- 6.5 10-3

2. This question can be solved only with hardware