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Select all that apply. Choose all the common ions that are isoelectronic with Ne. O Ap+ 0 F O Ca2+ K+ Mg2+ Nat o 13 02- Broct
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Answer #1

Ne has 10 electrons

Al3+:

Atomic number of Al = 13

So, number of electrons in Al = 13

Since charge on Al is +3

Number of electrons in Al3+ = 10

F-:

Atomic number of F = 9

So, number of electrons in F = 9

Since charge on F is -1

Number of electrons in F- = 10

Ca2+:

Atomic number of Ca = 20

So, Ca2+ has 18 electron

K+:

Atomic number of K = 19

So, K+ has 18 electron

Mg2+:

Atomic number of Mg = 12

So, Mg2+ has 10 electron

Na+:

Atomic number of Na = 11

So, Na+ has 10 electron

N3-:

Atomic number of N = 7

Number of electrons in N3- = 10

O2-:

Atomic number of O = 8

Number of electrons in O2- = 10

Br-:

Atomic number of Br = 35

Number of electrons in Br- = 36

C4-:

Atomic number of C = 6

Number of electrons in C4- = 10

Cl-:

Atomic number of Cl = 17

Number of electrons in Cl- = 18

S2-:

Atomic number of S = 16

Number of electrons in S2- = 18

Li+:

Atomic number of Li = 3

Number of electrons in Li = 2

Answer:

Al3+, F-, Mg2+, Na+, N3-, O2-, C4-

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