Question

Which of the following species are isoelectronic with Ne? Check all that apply.

mg2+
Ca
Li+
Al3+
F-
Na+
Li

Answer 1

Concepts and reason

The concept used to solve this problem is to determine the Iso-electronic species with neon on the basis of total number of electrons in the given species,

Fundamentals

Iso-electronic means the atoms of different elements which have same number of electrons

The number of electrons in any species is equal to the atomic number.

The atomic symbol notation is as follows:

Here The charge of an ion is showed by + or – sign on the right side super script.

: The atomic number of magnesium is 12; hence, it has 12 electrons. The ion is formed by losing two electrons in it which is indicates by its +2 charge. Therefore; the number of electrons in is 10.

: The atomic number of calcium is 20; hence, it has 20 electrons.

: The atomic number of lithium is 3; hence, it has 3 electrons. The ion is formed by losing one electron in it which is indicates by its +1 charge. Therefore; the number of electrons in is 2.

: The atomic number of aluminum is 13; hence, it has 13 electrons. The ion is formed by losing three electrons in it which is indicates by its +3 charge. Therefore; the number of electrons in is 10.

: The atomic number of fluorine is 9; hence, it has 9 electrons. The ion is formed by accepting one electrons in it which is indicates by its -1 charge. Therefore; the number of electrons in is 10.

: The atomic number of sodium is 11; hence, it has 11 electrons. The ion is formed by losing one electron in it which is indicates by its +1 charge. Therefore; the number of electrons in is 10.

: The atomic number of lithium is 3; hence, it has 3 electrons.

The atomic number of neon, Ne is 10 hence it has 10 electrons.

The following species also contains 10 electrons:

Therefore,, and are iso-electronic with neon.

Ans:

Thus; , , and are iso-electronic with neon.