Question

(8 points) The following data were taken from a voltage measurement on a noisy system: 1.37, 1.84, 1.35, 1.47, 1.10, 1.73, 1.54, 1.08 (all in mV). The standard deviation (o) of the data set is 5. 0.271 mV. (a) (b) Assuming the noise is random, what is the S/N ratio? How many measurements need to be averaged in order to achieve S/N=10?

Answer 1

We know the formula - Signal Power Noine Power 10 Calculate RMS noire voltage formula or = 20log RMs Singral voll - RMy hoise vollege J Alz an le?- 167° J9 -> 92-31 933) -A12 hese = -AlsqeSAD -2² - A2 A Step size o singhaul 26- RMS noire voltage a A = Vmax - Umin ntno ofreasurement RM svoltage = Vrax-Unin - Umax-Wrin = Vfs 282 Softs = 2^xA So over all RMS voltage = 2^xA so (s) = 20log (RMs Singinal voltage 1 RMS hoire Voltage = 200 103( ) => 20(103 (22) (4 r = 20 log2r + 20log J3/2. The JB - 6029 +176- A Choof reasurwint a) from 1 = 6.02x8+176 = 48.16+1.76 - Tug. 92 ks 6) 1 & 2 = 1o give 10=6.020n +1.76 10-1.76 = 6.02xh na 8.24 - Th=1.36) 6.02 measurement needtobe