Question

Montgomery, Physics 1 InScratchi placed 0.5 meters (nox)from the fulcrum (or axis of rotation) at tbe very end of tbe plank, what is the mass of the wooden plank? (Assume the plank is uniform) 4A 2 kg box is sitting on a uniform wooden plank that is 2 meters long, the box balances the plank when it is 4) 9 FN Identify and label the relevant variable with their corresponding rolank rba rbox=oism Plegtheim values. Mplank Write the full equation used and algebraically solve for the unknown using only symbols (no numbers) xcg =MPlenkxptnk +mtox Xbox . mplenk-Won u Waank BPaktkbo Plug in the values and solve for the numerical valve of the unknown CASM(wptankit 29)( s Xplank wek boxxbox) plankh 5) A uniform wood bcam (mwood 200 kg and L 6 meter) is resting on two scales at either end of the beam, a load of bricks (mricks 500 kg) is placed on the beam iks 4 meters from the end, Bob (mBob 100 kg) is standing on the wood beam roblm from the end. What does scales 1 and scale 2 read in Newton's? Identify and label the relevant variable with their corresponding values.. 5) Scale 1: Scale 2: Bricks Write the full equation used and algebraically solve for the unknown using only symbols (no numbers) Scale 1 Scale 2 Plug in the values and solve for the numerical valve of the unknown, Page 2 of 4

can you please help me with these two questions?

Thanks

Answer 1

. 0.5m, orang mos = 2 kg length l= 24 FN ua.or. Mov v3 9 - 0.5м., =1x9.8 anerk = 1 5 m 140.5 = 0.5m Empirotto Care wo planec (splank) - Won Goon so that planex 9) (eplack) - Mbon (9) aborto Woox FN ogranke plugin values Implande (9.996.9) – 2(9.8) (0.5) 30 mood of moviciging my lank = 2kg 6 mwood = 200kg 2=6m Mborder=500kg bricks = 4m moobalooley hisob- lm EMAJO Prue (m bob 9) "Gost "une () am bricks 9 (abricks) usz (1)=0 bod Los fy to the S 81tf2 - Mbong - oned 9 Mibricks g o L 4,600x9.4)(0)+200(9.8)() + 500 (9.8) (4) - sy @) o 1=4410N scate reading 4 § + 4410 -10.6.) - 200(9.9) - 1500 (9.8) THE 3430 N Scale reeding Lory eorick4M