The acoustic impedance of the matching layer is 14 x 106 kg.m -2 .s -1 Material...
The acoustic impedance of the matching layer is 14 x 106 kg.m -2 .s -1
|
Material |
Speed of Sound m .s -1 |
Density kg.m -3 |
|
Soft Tissue |
1540 |
1060 |
|
PZT |
3850 |
7600 |
c)Calculate the improvement in transmission from PZT to tissue due to the matching layer.
Homework Answers
c )
given
The acoustic impedance of the matching layer is 14 x 106 kg.m -2 .s -1
|
Material |
Speed of Sound m .s -1 |
Density kg.m -3 |
|
Soft Tissue |
1540 |
1060 |
|
PZT |
3850 |
7600 |
here say T ' is trial transmission ratio
= T1 x T2
= 0.67735 x 0.208851
= 0.135201
so the increase in transmission coefficient percentage is
= T ' - T / T
= 0.135201 - 0.10568 / 0.10568
= 0.27934
= 0.27934 x 100 %
so the improvement in transmission from PZT to tissue due to the matching layer is = 27.934 %
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