Question

A pulley of moment of inertia 2.5 kg. m is mounted on a wall as shown in the following figure. Light strings are wrapped around two circumferences of the pulley and weights are attached. Assume the following data: 11 = 49 cm, 12 = 20 cm, m1 = 1.0 kg, and m2 = 2.5 kg. (a) What is the angular acceleration of the pulley? (Enter the magnitude in rad/s2.) 0.0392 x rad/s2 (b) What is the linear acceleration (in m/s2) of the weights? (Indicate the direction with the signs of your answers. Assume the upward direction is positive.) a = 0.019208 x m/s2 12 = -0.00784 x m/s2

they answered it wrong the first time

Answer 1

s = 49cm r2 =20cm m, =lky m2 = 2.5kg I=2.5 kg m² The equation of motion migr, - m2 gr2 = Id a min - M22 9 @ I 2- IX 0149 - 215 X0.20 x 9.81 2.5 Id=-0.039 rad/sec? (6 The rotation is in clock wise direction. So angular momen acceleration is negative. The Linear accelerations of the masses. a = – 8,2 A2 = 8₂2 a = – 0.49 x60.039) Tai = +0.019 sep /sec2 A₂ = 0,20x0.039) 1a =-0.0078 / Seca)