3:
Here we have
P(A) = 0.90, P(B) = 0.70, P(A and B) = 0.65
Since P(A and B) is not equal to P(A)P(B) so A and B are not independent.
By the additional rule,
P(A or B) = P(A) + P(B) - P(A and B)= 0.9 +0.7 - 0.65 = 0.95
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P(A |B) = P(A and B) / P(B) = 0.65 / 0.70 = 0.9286
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4:
Gold medal can be awarded in 64 ways, silver in 63 ways and bronze is 62 ways so possible number of ways of awarding medal is
64 *63 * 62 = 249984
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5:
3. Two different events can occur called A and B. The probability that A occurs is...
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Twenty students are to be assigned to three groups: two will contain five members and the remaining ten are in the third group. Each student can only serve on one committee. How many distinct ways can this be done? (Hint: does order matter? The binomial coefficient is used for two groups, for more than two groups use the multinomial formula.)
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