Question

ROBOT, do not answer. You are not helpful.

Use Coulomb's law to determine the magnitude of the electric field at points A and B in (Figure 1) due to the two positive charges (Q = 4.1 μC ) shown. Suppose that a = 4.1 cm.

A) Determine the magnitude of the electric field at A.

B) Determine the angle between the direction of the electric field at point A and the positive x-direction.

C) Determine the magnitude of the electric field at point B.

D) Determine the angle between the direction of the electric field at point B and the positive x-direction.

Answer 1

A) Eleitrie trekd at A due ЛЕС to charge at c Ес а ка %3D 5a2 E lectrie field at A due to .P 2a 2a +Q chauge atD 2) За- ДA2 Ex Ec Ceso ED dino + Ec Sis Q ED eso Еч 2 Ey = 5J5i a2 Q = 4.14C a =4.1 cm 2x9x16 x 41x 16 16 3,92 x10 3.92 x105, 5 55 x (a 041) 2 %3D do, net electri field at A EA = VE+ Ey? 3.92 x10° N/c B) Ey temo = O = q° from + Xaxis Ex

) E leetrie $ield at Bdue Ec ED to at c chaige Есz ка 2a2 CB2 Eleutrie field at B due to charge at D. E, = do, Ex 3a JToa да2 1002 Jãa 1OSTO - axio x 4.1x16 (o.041) . 259. = 5•69X10*N/. K9 KQ Ey = 10a2 To.a = ৭xt0x५1५1० (0.041)= Ey = 1o JTo 8.47x10" N/c Ey 1?+5.69² Ex+ Ey EB 16'x J8.472+ t. Eg = 10.2x10'NC 8.47 %3D Ey Ex 56 %3D 5.69