Question

8. In the circuit at right. L-3.500 H, R-4.200 , and C=655.2 pF. Vac) is the input driving voltage with an mms value of 350 mV. a. Assuming light damping (small R. what is the resonant frequency of the circuit? (In other words to what frequency is the circuit tuned"?) A 88.1 MHZ D. 101.9 MHZ B 90.3 MHz E. 105.7 MHz C. 94.7 MHz FC 26 : f i = 10so a9 140 Hz Suppose that can drives the circuit at exactly the resonant natural frequency that you found in part (a). b. At this frequency, what is the total impedance of the circuit? (Hint: This time, this should require only minimal calculation) A. 0.6111 B 1.218 C.4.2009 D. 21.28 E 61.11 c. Find the rms current in the circuit: CA0.833.mA D 5.88 mA B 1.44 mA E. 7.77 mA C. 3.55 mA os sou - Iras (4.2) Iras = 8.36104 d. What would happen to each of the above two answers if the frequency of Vict) were increased to TWICE the resonant (natural) frequency? total impedance A increase B. remain unchanged C. decrease Cwren A. increase B. remain unchanged C. decrease Vars = 7 ,2 e. What would happen to each of the above two answers if the frequency of Vict) were decreased to HALF the resonant (natural) frequency? Total imgelance A increase B. remain unchanged C. decrease current: A increase B. remain unchanged C. decrease

d and e please

Answer 1

VO I wise The Resonant Lorequency - 2x 105. 142. = 210.2H2. 00 . Totul impedence: za V123 Htc-] X = 207h = 20x210.2x3.5x10918_467 4.6222 x C 2 H Ip-ax & S-43ở -1155, 2. 200 1.00 2.00 3.00 (x2-x) = 3.47.00 at 216.5 m Hà Greguney (x - x ) = (2.31 - 231)=0 at 105 regen 5.00 16.00 vening Total impedence will increase. ^ Increase sms Current wil decrease due to increasing impedance so © decrease

@ keep in mind. Impedance occurring at Resonant Frequency is minimum. When increase or decrease the frequency when the supply frequency rega er then Or less than the Resonand frequency The impedance will increase So answer 6 Increase is Correct. for sms Current © decrease