If a non-cyclic alkane shows a molecular ion peak at m/z 3.80 × 102, what is the chemical formula?
A non-cyclic alkane shows a molecular ion peak at m/z 3.80 × 102= 380
Let n be the number of carbons in the alkane.
Then the number of hydrogens is 2n+2. The combined
weight of the carbons plus the combined weight of the hydrogens
must add up to 380. So we have:
12xn + 1x(2n+2) = 380
12n+2n+2 = 380
n = 378/14 = 27
we get n = 27 and 2n+2 = 56
Therefore the molecular formula of non-cyclic alkane is
C27H56.
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