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A sanding disk with rotational inertia 5.8 x 10 kg m2 is attached to an electric...
10. The angular momentum of a flywheel having a rotational inertia of 0.140 kg m2 about...
10. The angular momentum of a flywheel having a rotational inertia of 0.140 kg m2 about its central axis decreases from 3.00 to 0.800 kg m'/s in 1.50 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the average power of the flywheel?...
A disk with a rotational inertia of 5.0 kg · m2 and a radius of 0.25...
A disk with a rotational inertia of 5.0 kg · m2 and a radius of 0.25 m rotates on a frictionless fixed axis perpendicular to the disk and through its center. A force of 8.0 N is applied along the rotation axis. The angular acceleration of the disk is? The answer is 0, but how?
The rotor of an electric motor has rotational inertia Im = 4.54 x 10-3kg.m2 about its...
The rotor of an electric motor has rotational inertia Im = 4.54 x 10-3kg.m2 about its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertia l = 14.3 kg.m² about this axis. Calculate the number of revolutions of the rotor required to turn the probe through 18.4° about its central axis. Number Units
The rotor of an electric motor has rotational inertia I_m = 4.41 times 10^-3 kg middot...
The rotor of an electric motor has rotational inertia I_m = 4.41 times 10^-3 kg middot m^2 about its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertia I_rho = 7.77 kg middot m^2 about this axis. Calculate the number of revolutions of the rotor required to tum the probe through 44.8 degree...
The rotor of an electric motor has rotational inertia Im = 2.82 x 103 kg-mabout its...
The rotor of an electric motor has rotational inertia Im = 2.82 x 103 kg-mabout its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertial, = 14.2 kg.m2 about this axis. Calculate the number of revolutions of the rotor required to turn the probe through 31.5° about its central axis. Number Units
A disk with moment of inertia 9.15 × 10−3 kg∙m^2 initially rotates about its center at...
A disk with moment of inertia 9.15 × 10−3 kg∙m^2 initially rotates about its center at angular velocity 5.32 rad/s. A non-rotating ring with moment of inertia 4.86 × 10−3 kg∙m^2 right above the disk’s center is suddenly dropped onto the disk. Finally, the two objects rotate at the same angular velocity ?? about the same axis. There is no external torque acting on the system during the collision. Please compute the system’s quantities below. 1. Initial angular momentum ??...
A cylinder with rotational inertia I1 = 3.2 kg · m2 rotates clockwise about a vertical...
A cylinder with rotational inertia I1 = 3.2 kg · m2 rotates clockwise about a vertical axis through its center with angular speed ω1 = 5.8 rad/s. A second cylinder with rotational inertia I2 = 1.2 kg · m2 rotates counterclockwise about the same axis with angular speed ω2 = 6.2 rad/s. If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)? What percentage of the original kinetic energy...
1a. 1b. A disk with a rotational inertia of 1.20 kg·m2 rotates like a merry-go-round while...
1a.
1b. A disk with a rotational inertia of 1.20 kg·m2
rotates like a merry-go-round while undergoing a torque given by
τ = (4.01 + 2.79t) N · m. At time t =
1.00 s, its angular momentum is 3.53 kg·m2/s. What is
its angular momentum at t = 3.00 s?
In the figure here, three particles of mass m = 0.013 kg are fastened to three rods of length d = 0.13 m and negligible mass. The rigid assembly...
The rotational system below has an inertia I = 50 kg m2 and a viscous damping...
The rotational system below has an inertia I = 50 kg m2 and a viscous damping con- stant c 10N -m s/rad. The torque T(t) is applied by an electric motor. From a free body diagram, the equation of motion can be shown to be dw 50 +10w= T(t) dt If the electrical system's inductance L tion for the field current 0.001 H and the resistance R = 5 , the equa- is is dis +5iy = v(t) 0.001 dt...
please help ASAP The angular momentum of a flywheel having a rotational inertia of 0.848 kg.mabout...
please help ASAP
The angular momentum of a flywheel having a rotational inertia of 0.848 kg.mabout its central axis decreases from 3.00 to 0.870 kg.m/s in 4.20 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the magnitude of the average power done...
10. The angular momentum of a flywheel having a rotational inertia of 0.140 kg m2 about its central axis decreases from 3.00 to 0.800 kg m'/s in 1.50 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the average power of the flywheel?...
The rotor of an electric motor has rotational inertia Im = 4.54 x 10-3kg.m2 about its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertia l = 14.3 kg.m² about this axis. Calculate the number of revolutions of the rotor required to turn the probe through 18.4° about its central axis. Number Units
The rotor of an electric motor has rotational inertia I_m = 4.41 times 10^-3 kg middot m^2 about its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertia I_rho = 7.77 kg middot m^2 about this axis. Calculate the number of revolutions of the rotor required to tum the probe through 44.8 degree...
The rotor of an electric motor has rotational inertia Im = 2.82 x 103 kg-mabout its central axis. The motor is used to change the orientation of the space probe in which it is mounted. The motor axis is mounted along the central axis of the probe; the probe has rotational inertial, = 14.2 kg.m2 about this axis. Calculate the number of revolutions of the rotor required to turn the probe through 31.5° about its central axis. Number Units
1a.
1b. A disk with a rotational inertia of 1.20 kg·m2
rotates like a merry-go-round while undergoing a torque given by
τ = (4.01 + 2.79t) N · m. At time t =
1.00 s, its angular momentum is 3.53 kg·m2/s. What is
its angular momentum at t = 3.00 s?
In the figure here, three particles of mass m = 0.013 kg are fastened to three rods of length d = 0.13 m and negligible mass. The rigid assembly...
The rotational system below has an inertia I = 50 kg m2 and a viscous damping con- stant c 10N -m s/rad. The torque T(t) is applied by an electric motor. From a free body diagram, the equation of motion can be shown to be dw 50 +10w= T(t) dt If the electrical system's inductance L tion for the field current 0.001 H and the resistance R = 5 , the equa- is is dis +5iy = v(t) 0.001 dt...
please help ASAP
The angular momentum of a flywheel having a rotational inertia of 0.848 kg.mabout its central axis decreases from 3.00 to 0.870 kg.m/s in 4.20 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the magnitude of the average power done...
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