Homework Answers
To find the flux we use the relation between the field through a surface and flux through the surface, and to find charge we use Gauss's law as shown below in problem 9
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8. At every point on the surface of a sphere of radius 0.4 m the electric...
The electric field everywhere on the surface of a charged sphere of radius 0.208 m has...
The electric field everywhere on the surface of a charged sphere of radius 0.208 m has a magnitude of 550 N/C and points radially outward from the center of the sphere. (a) What is the net charge on the sphere? (b) What can you conclude about the nature and distribution of charge inside the sphere?
The electric field everywhere on the surface of a thin, spherical shell of radius 0.790 m...
The electric field everywhere on the surface of a thin, spherical shell of radius 0.790 m is of magnitude 895 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface?
The electric field everywhere on the surface of a thin, spherical shell of radius 0.745 m...
The electric field everywhere on the surface of a thin, spherical shell of radius 0.745 m is of magnitude 867 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface? nC
A solid conducting sphere of radius 2.00 cm has a charge of 9.20 μC. A conducting...
A solid conducting sphere of radius 2.00 cm has a charge of 9.20 μC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of-1.92 μC. Find the electric field at the following radii from the center of this charge configuration (a) r-1.00 cm magnitude 0 direction N/C The magnitude is zero. (b) r-3.00 cm magnitude 9.2e7 direction radially outward (c) r-4.50 cm magnitude 0 direction...
The electric field everywhere on the surface of a thin, spherical shell of radius 0.710 m...
The electric field everywhere on the surface of a thin, spherical shell of radius 0.710 m is of magnitude 932 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface? ive calculated this out and i get 5.22E-8, but the computer system my school uses is saying thats wrong
(a) A solid sphere, made of an insulating material, has a volume charge density of p...
(a) A solid sphere, made of an insulating material, has a volume charge density of p , where r is the radius from the center of the sphere, a is constant, and a >0. What is the electric field within the sphere as a function of the radius r? Note: The volume element dv for a spherical shell of radius r and thickness dr is equal to 4tr2dr. (Use the following as necessary: a, r, and co.) magnitude E direction...
4. a- A Gaussian sphere with radius 1.20 m encloses a point charge Q1 = 2.20×10–6...
4. a- A Gaussian sphere with radius 1.20 m encloses a point charge Q1 = 2.20×10–6 C at the spherical center. The electric flux through the spherical surface is measured to be 1. Now Q1 is removed, and another point charge Q2 = –8.80×10–6 C is placed at the spherical center. The electric flux through the spherical surface is then measured to be 2. What is 2/1? b- A Gaussian sphere with radius 1.20 m encloses a point charge Q1...
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is.....
If a charge is located at the center of a spherical volume and
the electric flux through the surface of the sphere is...
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is phi, what would be the flux through the surface if the radius of the sphere were tripled?
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is Φ...
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is Φ, what should be the flux through the surface if the radius of the sphere were tripled? Draw the diagram with a sphere of radius R and the second surface of radius 3R. Draw enough field lines to illustrate the field. Calculate the flux through each surface. What is the relationship of the flux through radius R...
(10 points) a) Two through the box? charges Qi and Q2 are inside a closed cubical...
(10 points) a) Two through the box? charges Qi and Q2 are inside a closed cubical box of side a. What is the net outward flux iv. (Qi + Q)/(4a) b) As two positive charges are brought closer together i. the repulsive force between them will decrease in magnitude ii. the repulsive force between them will increase in magnitude ii. the attractive force between them wil decrease in magnitude iv. the attractive force between them will increase in magnitude v....
A solid conducting sphere of radius 2.00 cm has a charge of 9.20 μC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of-1.92 μC. Find the electric field at the following radii from the center of this charge configuration (a) r-1.00 cm magnitude 0 direction N/C The magnitude is zero. (b) r-3.00 cm magnitude 9.2e7 direction radially outward (c) r-4.50 cm magnitude 0 direction...
(a) A solid sphere, made of an insulating material, has a volume charge density of p , where r is the radius from the center of the sphere, a is constant, and a >0. What is the electric field within the sphere as a function of the radius r? Note: The volume element dv for a spherical shell of radius r and thickness dr is equal to 4tr2dr. (Use the following as necessary: a, r, and co.) magnitude E direction...
If a charge is located at the center of a spherical volume and
the electric flux through the surface of the sphere is...
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is phi, what would be the flux through the surface if the radius of the sphere were tripled?
(10 points) a) Two through the box? charges Qi and Q2 are inside a closed cubical box of side a. What is the net outward flux iv. (Qi + Q)/(4a) b) As two positive charges are brought closer together i. the repulsive force between them will decrease in magnitude ii. the repulsive force between them will increase in magnitude ii. the attractive force between them wil decrease in magnitude iv. the attractive force between them will increase in magnitude v....
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