Question

Name For cadh e position v time graphs below illustrates the position of freo falling objectas. graph, determine the a initial height, h,; b. initial vclocity, v c. maximum height, d. final velocity, v, of the trip, e. total time of the trip. The acceleration of all object is -10 m/s?

Answer 1

FIRST GRAPH (a) h_i = 20 m (b) v_i = (40 - 20) m/(0.5 - 0) s = 20/0.5 ms^-1 = 40 ms^-1 INITIAL VELOCITY (SLOPE OF GRAPH B/W t = 0 to t = 0.5 sec) (c) Hence = v_1^2 sin^2 theta/2g = (40)^2 (sin 75.96 degrees)^2/2 times 9.8 = 76.83 m tan theta = 4/1 = 4 theta = 75.96 (d) From v^2 = u^2 + 2as v_xf^2 = v_xi^2 + 2 (theta) a_x = 0 v_xf = v_xi = v_1 cos theta = (40) cos 75.96 degrees = 9.70 ms^-1 Ans v_yf^2 = v_yi^2 + 2g (theta) y = 0 AT FINAL POINT v_yf^2 = v_yi^2 v_yf = v_yi = v_i sin theta = (40) sin 75.96 degrees = 38.80 m/s therefore v_f = squareroot v_yf^2 + v_yf^2 = squareroot 9.70^2 + 38.80^2 = 40.0 m/s TOTAL TIME OF TRIP t = 8.5 sec (FROM GRAPH)

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