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004 (part 1 of 3) 10.0 points A 0.878 kg particle has a speed of 4.8 m/s at point A and kinetic energy of 6.4 J at point What
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Answer #1

m = 0.878 kg VA - 4.8 m/s EBF 6.45 EA = 1 mV 1 x 0.878x (4.8) ² - 10.11 ] & EB = 1 m voz 6.4 = 1 +0.878 Vo² 12.8 - 14.578 0.8

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