Question

matlap

3, Programmi ng Polynomial interpolation has been known sample points are plotted ys different ways (at least two) resulting curve matlab program ys [0 0.9 0.6 10 0.1-0.3 -0.7 -0.9 -0.21: %EHM#*A ys xs=0:length (ys) -1; x-0:0.1:1ength (ys) -1;

Answer 1

Given the data points (xs,ys), we plot the curve at the data points in x using Matlab code below:

Required Matlab code with explanatory comments is below:

START CODE

ys=[0 0.9 0.6 1 0 0.1 -0.3 -0.7 -0.9 -0.2]; %y sample points
xs=0:length(ys)-1; %x sample points
x=0:0.1:length(ys)-1; %x data points
p3=polyfit(xs,ys,3); %fit third degree polynomial to (xs,ys)
p7=polyfit(xs,ys,7); %fit seventh degree polynomial to (xs,ys)
plot(xs,ys,'ro'); %plot sample points as red dots
hold on
plot(x,polyval(p3,x),'b--'); %plot as blue dashed lines
plot(x,polyval(p4,x),'g--'); %plot as green double dashed lines
legend('Sample points','3rd degree polynomial', '7th degree polynomial', 'Location', 'NorthEast') %add a legend

END CODE

Resulting plot is below:

1 C Sample points 0.8 3rd degree polynomial 7th degree polynomial 0.6 0.4 0.2 0. -0.4 -0.6 -0.8 -1 4 0 1 2 3 5 6 7 8 N

$\blacksquare$

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