Homework Answers
1) Potential energy of the system of charges, U = kq0q/r
U = 9*10^9*0.8*10^-6*2*10^-6/0.8 = 18 mJ
Answer = 18
2) Kinetic energy of q = 1/2mv^2 = change in potential energy
U1 = 18 mJ
U2 = 9*10^9*0.8*10^-6*2*10^-6/2.0 = 7.2 mJ
1/2 *0.08*10^-3 *v^2 = (18-7.2)*10^-3 J
v = 16.43 m/s
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