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A skier is traveling at a speed of 39.5 m/s when she reaches the base of...
A skier approaches the base of an icy, frictionless hill with a speed of Vo. As...
A skier approaches the base of an icy, frictionless hill with a
speed of Vo. As the skier travels up the slope, the skier slows
down. Find the HORIZONTAL and VERTICAL accelerations, NOT the
acceleration of the slope. Use the x-y axes shown with horizontal
rightward and vertical upward as positive. The initial velocity, Vo
= 10.2 m/s The angle of the hill, b = 15° Cannot figure this thing
out.I tried using -9.8Cos/Sin(15 but that was incorrect
A 72.5-kg skier coasts up a snow-covered hill that makes an angle of 22.9 ° with...
A 72.5-kg skier coasts up a snow-covered hill that makes an angle of 22.9 ° with the horizontal. The initial speed of the skier is 8.71 m/s. After coasting a distance of 1.19 m up the slope, the speed of the skier is 3.74 m/s. (a) Find the work done by the kinetic frictional force that acts on the skis. (b) What is the magnitude of the kinetic frictional force?
A skier with mass 64.0 kg starts at rest at the top of an 842 m...
A skier with mass 64.0 kg starts at rest at the top of an 842 m long ski slope, which makes an angle 13.0 ∘ with the horizontal. A typical coefficient of friction between skis and snow is 5.20×10−2. skiers don't go straight down the hill- they zigzag back and forth. Even though they still end up at the bottom of the hill, they've lost more energy to friction because friction is a non-conservative force. Let's say due to zigzagging,...
An 90 kg skier starts from rest at the top of a ski run. She quickly...
An 90 kg skier starts from rest at the top of a ski run. She quickly finds herself going fast down the icy (essentially frictionless) hill. At the base of the hill she is unable to stop. She skis across an icy deck, through the open doors of the ski lodge; across the concrete floor of the rental shop before coming to rest against the back wall of the shop. The height of the hill is 150m, the deck and...
A skier is pulled by a tow rope up a frictionless ski slope that makes an...
A skier is pulled by a tow rope up a frictionless ski slope that makes an angle of 8.9° with the horizontal. The rope moves parallel to the slope with a constant speed of 1.1 m/s. The force of the rope does 640 J of work on the skier as the skier moves a distance of 5.9 m up the incline. (a) If the rope moved with a constant speed of 2.4 m/s, how much work would the force of...
A 68 kg skier starts from rest at a height of H = 24 m above...
A 68 kg skier starts from rest at a height of H = 24 m above the end of the ski-jump ramp. As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless. End of ramp (a) What is the maximum height h of his jump above the end of the ramp? (b) If he increased his weight by putting on a backpack,...
A skier traveling at 23 m/s encounters a 17.6 degree slope. If you could ignore friction,...
A skier traveling at 23 m/s encounters a 17.6 degree slope. If you could ignore friction, to the nearest meter, how far up the hill does he go?
Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to...
Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to check your answers. A)A skier moving at 4.25 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220 with her skis. How far does she travel on this patch before stopping? B)Suppose the rough patch in part A was only 2.89 m long. How fast would the skier be moving when she reached the end of the...
A 62.0 kg skier is moving at 6.50 m/s on a frictionless, horizontal snow covered plateau when she encounters a rough patch 3.50 m long
A 62.0 kg skier is moving at 6.50 m/s on a frictionless, horizontal snow covered plateau when she encounters a rough patch 3.50 m long. The coefficient of kinetic friction between this patch and returning to friction-free snow, she skis down an icy, frictionless hill 2.50 m high. (a) How fast is the skier moving when she gets to the bottom of the hill? (b) How much internal energy was generated in crossing the rough patch?
A skier is pulled by a towrope up a frictionless ski slope that makes an angle...
A skier is pulled by a towrope up a frictionless ski slope that makes an angle of 12 degrees with the horizontal. The rope moves parallel to the slope with a constant speed of .0m/s. The force of the rope does 900J of work on the skier as the skier moves a distance of 8.0m up the incline. (a) If the rope moed with a constant speed of 2.0m/s, how much work would the force of the rope do on...
A skier approaches the base of an icy, frictionless hill with a
speed of Vo. As the skier travels up the slope, the skier slows
down. Find the HORIZONTAL and VERTICAL accelerations, NOT the
acceleration of the slope. Use the x-y axes shown with horizontal
rightward and vertical upward as positive. The initial velocity, Vo
= 10.2 m/s The angle of the hill, b = 15° Cannot figure this thing
out.I tried using -9.8Cos/Sin(15 but that was incorrect
An 90 kg skier starts from rest at the top of a ski run. She quickly finds herself going fast down the icy (essentially frictionless) hill. At the base of the hill she is unable to stop. She skis across an icy deck, through the open doors of the ski lodge; across the concrete floor of the rental shop before coming to rest against the back wall of the shop. The height of the hill is 150m, the deck and...
A 68 kg skier starts from rest at a height of H = 24 m above the end of the ski-jump ramp. As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless. End of ramp (a) What is the maximum height h of his jump above the end of the ramp? (b) If he increased his weight by putting on a backpack,...
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