Question

Question 8 The nylon rope from which a mountain climber is suspended has a force constant of 1.40 x 104 N/m. How much would this rope stretch to break the climber's fall if he free-falls 2.16 m before the rope runs out of slack, given his mass plus and the mass of his equipment are 91.6 kg? Hint: Use conservation of energy. You can assume the amount the rope stretches is small compared to the distance of his fall. Select the correct answer O 52.6cm O 46.2cm O 58.7 cmAnswer O 43.5 cm O 46.0 cm CHECK ANSWER of 2 attempts used LAST ATTEMPT!

Answer 1

As HOMEWORKLIB RULES guide lines i did 8 only

8)

from conservation of energy

PEelastic =PEgravitational

1/2*k*x^2 =m*g*h

k*x^2 =2*m*g*h

x^2 =2*m*g*h/(k)

x = sqrt((2*m*g*h)/(k))

=sqrt((2*91.6 kg*9.80 m/s^2*2.16 m)/(1.40*10^4 N/m))

x = 0.52630 m

x = 52.6 cm

option A is correct