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A point rotates about the origin in the xy plane at a constant radius of 0.102...

A point rotates about the origin in the xy plane at a constant radius of 0.102 m and angular velocity of 8.91 rad/s. As you know, the projections of this point on the x- and y-axes undergo simple harmonic motion. A. What is the amplitude of this motion? B. What is its frequency? C. What is its period?
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Answer #1
amplitude = radius= 0.102m
frequency, f= angular velocity/ 2pi=1.42Hz
time period= 1/f=0.70 sec
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