Question

In parallel plate capacitors, the area of one plate is A and the two conductor plates are separated from each other by d. At the center of the two conductor plates, a metal plate of thickness a and not charged was inserted. (The dielectric of the empty space is air (? 0)

(a) Determine the capacitance of this device. (5)

(b) If a metal plate with a thickness of almost zero is inserted, this metal plate appears to have no influence on the original capacitance, and explain the phenomenon. (5)

(c) How will the capacitance change when the metal plate is placed in the space between the upper plate and the capacitor, not the center of the capacitor? Expressed in the formulas and described in comparison with (a). (5)

+ + + + + ib da

Answer 1

AY Cfor ai Ex Area A E A Cogiad cofactae) capacitance is inserted of ttickness Plate capae tarze a When Series capacitors. as acts tapacitor then Re A 2EA Ca d-a d-a d-a d-a aeA deA Ceg 2d-2a aCd-a) CA Cer d-a

Bero) nserted thiceness Cby IF a Plate acts ther capacitor Platej Tho blui the a Series capact ton. C2 C22 d/2 ae A Ceq 2 d Cea EA aeA EA Ce -7 equai to apacitaure CI d-a dIa C3

A EA C27 d-a b aeA CA d-a d-a 2 Cea d-a e A e A d-a d-a eA 니eA t Cd-a) d-a 4eA 늬 Cd-a) d-a ceq ae A EA Ceg= d-a 1